ASVAB Electronics Information Practice Test 429037 Results

Your Results Global Average
Questions 5 5
Correct 0 3.19
Score 0% 64%

Review

1 Use Ohm's Law to calculate the value of current in this circuit if voltage is 405 volts and resistance is 90 Ω.
81% Answer Correctly
6 A
9 A
1.5 A
4.5 A

Solution

Ohm's law specifies the relationship between voltage (V), current (I), and resistance (R) in an electrical circuit: V = IR.

Solved for current, I = \( \frac{V}{R} \) = \( \frac{405}{90} \) = 4.5 A


2

What is the voltage of most household electrical systems in the United States?

59% Answer Correctly

220V

60V

60Hz

110V


Solution

Most households use electricity with a voltage of 110V.


3

This circuit diagram represents a(n):

69% Answer Correctly

parallel circuit

open circuit

series-parallel circuit

series circuit


Solution

A series circuit has only one path for current to flow. In a series circuit, current (I) is the same throughout the circuit and is equal to the total voltage (V) applied to the circuit divided by the total resistance (R) of the loads in the circuit. The sum of the voltage drops across each resistor in the circuit will equal the total voltage applied to the circuit.


4

The most common circuit configuration is:

59% Answer Correctly

series-parallel

household

series

parallel


Solution

Circuits are not limited to only series or only parallel configurations. Most circuits contain a mix of series and parallel segments. A good example is a household circuit breaker. Electrical outlets in each section of the house are wired in parallel with the circuit breaker for that section wired in series making it easy to cut off electricity to the parallel parts of the circuit when needed.


5 How would you connect 10 [9V 5A] batteries to achieve a combined power output of 9V 50A?
51% Answer Correctly
series
perpendicular
orthogonal
parallel

Solution

Connecting the 10 batteries in series multiplies their voltage while keeping their current the same yielding a 90V 5A configuration. Connecting the 10 batteries in parallel multiplies their current while keeping their voltage the same yieleding a 9V 50A configuration. Using a series-parallel connection, 5 batteries can be connected in series and 5 can be connected in parallel resulting in a 45V 25A configuration.