ASVAB Electronics Information Practice Test 453189 Results

Your Results Global Average
Questions 5 5
Correct 0 3.42
Score 0% 68%

Review

1 What's the overall power consumption of a piece of equipment that is rated for 6 amps at 60 volts?
80% Answer Correctly
360 W
364 W
361.5 W
720 W

Solution
Power is measured in watts (W) and 1 watt equals 1 ampere multiplied by 1 volt: P = \( V \times I \). For this problem, the equipment is rated for 6 amps (I) at 60 volts (V) so the equation becomes P = \( 60 \times 6 \) = 360 W

2

What is the frequency of most household electrical systems?

59% Answer Correctly

60Hz

110Hz

60MHz

110V


Solution

Electricity is delivered from power stations to customers as AC because it provides a more efficient way to transport electricity over long distances. Most households use electricity with a frequency of 60Hz.


3

Electrons will flow as current from areas of __________ potential (concentration of electrons) to areas of __________ potential.

74% Answer Correctly

low, high

high, low

low, low

high, high


Solution

Voltage (V) is the electrical potential difference between two points. Electrons will flow as current from areas of high potential (concentration of electrons) to areas of low potential. Voltage and current are directly proportional in that the higher the voltage applied to a conductor the higher the current that will result.


4

The valence shell of a semiconductor is how full of electrons?

67% Answer Correctly

half full

empty

more than half full

less than half full


Solution

Semiconductors have valence shells that are exacly half full and can conduct electricity under some conditions but not others. This property makes them useful for the control of electrical current.


5 How would you connect 10 [15V 25A] batteries to achieve a combined power output of 150V 25A?
53% Answer Correctly
series-parallel
series
perpendicular
orthogonal

Solution

Connecting the 10 batteries in series multiplies their voltage while keeping their current the same yielding a 150V 25A configuration. Connecting the 10 batteries in parallel multiplies their current while keeping their voltage the same yieleding a 15V 250A configuration. Using a series-parallel connection, 5 batteries can be connected in series and 5 can be connected in parallel resulting in a 75V 125A configuration.