ASVAB Electronics Information Practice Test 505721 Results

Your Results Global Average
Questions 5 5
Correct 0 3.59
Score 0% 72%

Review

1

The formula specifying Ohm's law is which of the following?

76% Answer Correctly

\(V = {I \over R}\)

\(V = {R \over I}\)

V = I2R

V = IR


Solution

Ohm's law specifies the relationship between voltage (V), current (I), and resistance (R) in an electrical circuit: V = IR.


2

In an electrical circuit, resistors have fixed or __________ resistance.

69% Answer Correctly

variable

parallel

series

dynamic


Solution

Resistors are used to limit voltage and/or current in a circuit and can have a fixed or variable resistance.  Variable resistors (often called potentiometers or rheostats) are used when dynamic control over the voltage/current in a circuit is needed, for example, in a light dimmer or volume control.


3

What is the frequency of most household electrical systems?

59% Answer Correctly

110Hz

60Hz

110V

60MHz


Solution

Electricity is delivered from power stations to customers as AC because it provides a more efficient way to transport electricity over long distances. Most households use electricity with a frequency of 60Hz.


4

A capacitor is often used for which of the following purposes?

68% Answer Correctly

to maintain power in a circuit when the primary power source is disconnected

as a primary power source

to allow a small amount of current to control a large amount of current

to convert alternating current into direct current


Solution

Capacitors store electricity and are used in circuits as temporary batteries. Capacitors are charged by DC current (AC current passes through a capacitor) and that stored charge can later be dissipated into the circuit as needed. Capacitors are often used to maintain power within a system when it is disconnected from its primary power source or to smooth out or filter voltage within a circuit.


5 What's the overall power consumption of a piece of equipment that is rated for 4 amps at 30 volts?
80% Answer Correctly
360 W
108 W
120 W
129 W

Solution
Power is measured in watts (W) and 1 watt equals 1 ampere multiplied by 1 volt: P = \( V \times I \). For this problem, the equipment is rated for 4 amps (I) at 30 volts (V) so the equation becomes P = \( 30 \times 4 \) = 120 W