ASVAB Electronics Information Practice Test 592474 Results

Your Results Global Average
Questions 5 5
Correct 0 3.64
Score 0% 73%

Review

1

Which of the following allows current to pass easily in one direction and blocks current in the other direction?

69% Answer Correctly

inductor

diode

capacitor

resistor


Solution

A diode allows current to pass easily in one direction and blocks current in the other direction. Diodes are commonly used for rectification which is the conversion of alternating current (AC) into direct current (DC). Because a diode only allows current flow in one direction, it will pass either the upper or lower half of AC waves (half-wave rectification) creating pulsating DC. Multiple diodes can be connected together to utilize both halves of the AC signal in full-wave rectification.


2

The watt is a unit of measurement for:

78% Answer Correctly

energy

power

frequency

resistance


Solution

Electrical power is measured in watts (W) and is calculated by multiplying the voltage (V) applied to a circuit by the resulting current (I) that flows in the circuit: P = IV. In addition to measuring production capacity, power also measures the rate of energy consumption and many loads are rated for their consumption capacity. For example, a 60W lightbulb utilizes 60W of energy to produce the equivalent of 60W of heat and light energy.


3

What type of current flows in only one direction in a circuit?

82% Answer Correctly

series

parallel

alternating

direct


Solution

Direct current flows in only one direction in a circuit, from the negative terminal of the voltage source to the positive. A common source of direct current (DC) is a battery.


4 A circuit with a 120-volt power supply is protected by a 5-amp circuit breaker. What is the largest number of watts loads on this circuit can safely use?
82% Answer Correctly
604 W
660 W
601.5 W
600 W

Solution
Wattage is current multiplied by voltage: W = IV. So, the maximum amount of power a 120-volt circuit with a 5A circuit breaker would allow is 120V x 5A = 600 W.

5 How would you connect 10 [12V 5A] batteries to achieve a combined power output of 12V 50A?
52% Answer Correctly
perpendicular
series-parallel
series
parallel

Solution

Connecting the 10 batteries in series multiplies their voltage while keeping their current the same yielding a 120V 5A configuration. Connecting the 10 batteries in parallel multiplies their current while keeping their voltage the same yieleding a 12V 50A configuration. Using a series-parallel connection, 5 batteries can be connected in series and 5 can be connected in parallel resulting in a 60V 25A configuration.