ASVAB Electronics Information Practice Test 692759 Results

	Your Results	Global Average
Questions	5	5
Correct	0	3.64
Score	0%	73%

Review

1 Use Ohm's Law to calculate the value of voltage in this circuit if resistance is 20 Ω and current is 10 amps.

85% Answer Correctly

	199 V
	204 V
	100 V
	200 V

Solution

Ohm's law specifies the relationship between voltage (V), current (I), and resistance (R) in an electrical circuit: V = IR.

V = \( I \times R \) = \( 10 \times 20 \) = 200 V

2 A circuit with a 120-volt power supply is protected by a 10-amp circuit breaker. What is the largest number of watts loads on this circuit can safely use?

82% Answer Correctly

	1200 W
	2400 W
	400 W
	1320 W

Solution

Wattage is current multiplied by voltage: W = IV. So, the maximum amount of power a 120-volt circuit with a 10A circuit breaker would allow is 120V x 10A = 1200 W.

Resistance is opposition to which of the following?

70% Answer Correctly

	impedance
	conductance
	current
	voltage

Solution

Resistance is opposition to the flow of current and is measured in ohms (Ω). One ohm is defined as the amount of resistance that will allow one ampere of current to flow if one volt of voltage is applied. As resistance increases, current decreases as resistance and current are inversely proportional.

One of the lights on your Christmas tree burns out and this causes the rest of the lights connected to that strand to go dark. How are the lights in that strand connected?

73% Answer Correctly

	series-parallel
	perpendicular
	parallel
	series

Solution

Lights connected in series form a chain with each light connecting to adjacent lights via one wire. Therefore, if one of the lights burns out and breaks the series, none of the other lights will receive power and they'll go dark. Lights connected in parallel each connect to the positive and negative nodes of the power source and would not go dark if one of their neighbors burnt out.

5 How would you connect 4 [12V 15A] batteries to achieve a combined power output of 48V 15A?

53% Answer Correctly

	series
	perpendicular
	parallel
	orthogonal

Solution

Connecting the 4 batteries in series multiplies their voltage while keeping their current the same yielding a 48V 15A configuration. Connecting the 4 batteries in parallel multiplies their current while keeping their voltage the same yieleding a 12V 60A configuration. Using a series-parallel connection, 2 batteries can be connected in series and 2 can be connected in parallel resulting in a 24V 30A configuration.