ASVAB Electronics Information Practice Test 800602 Results

Your Results Global Average
Questions 5 5
Correct 0 3.73
Score 0% 75%

Review

1

The hertz is a unit of measurement for:

81% Answer Correctly

energy

power

frequency

inductance


Solution

The hertz is a unit of measurement for frequency.


2

A solid state device has which of the following characteristics?

53% Answer Correctly

made from a mix of conductive and insulative material

made entirely from conductive material

made entirely from semiconductor material

made entirely from insulative material


Solution

The transistor is the foundation of modern electronic devices. It is made entirely from semiconductor material (making it a solid state device) and can serve many different functions in a circuit including acting as a switch, amplifier, or current regulator. A transistor works by allowing a small amount of current applied at the base to control general current flow from collector to emitter through the transistor.


3

Electrons will flow as current from areas of __________ potential (concentration of electrons) to areas of __________ potential.

74% Answer Correctly

high, low

low, low

low, high

high, high


Solution

Voltage (V) is the electrical potential difference between two points. Electrons will flow as current from areas of high potential (concentration of electrons) to areas of low potential. Voltage and current are directly proportional in that the higher the voltage applied to a conductor the higher the current that will result.


4

Which of these materials is not a good conductor of electricity?

79% Answer Correctly

gold

copper

air

tin


Solution

All conductors have resistance and the amount of resistance varies with the element. In general, metals make the best conductors of electricity and non-metals make the worst conductors of electricity.


5 What's the overall power consumption of a piece of equipment that is rated for 4 amps at 110 volts?
80% Answer Correctly
443 W
440 W
432 W
660 W

Solution
Power is measured in watts (W) and 1 watt equals 1 ampere multiplied by 1 volt: P = \( V \times I \). For this problem, the equipment is rated for 4 amps (I) at 110 volts (V) so the equation becomes P = \( 110 \times 4 \) = 440 W