ASVAB Electronics Information Practice Test 805671 Results

Your Results Global Average
Questions 5 5
Correct 0 3.33
Score 0% 67%

Review

1

This circuit component symbol represents a(n):

55% Answer Correctly

potentiometer

transformer

fuse

inductor


Solution

Resistors are used to limit voltage and/or current in a circuit and can have a fixed or variable resistance.  Variable resistors (often called potentiometers or rheostats) are used when dynamic control over the voltage/current in a circuit is needed, for example, in a light dimmer or volume control.


2

The ampere is a unit of measurement for:

79% Answer Correctly

current

power

inductance

energy


Solution

Current is the rate of flow of electrons per unit time and is measured in amperes (A). A coulomb (C) is the quantity of electricity conveyed in one second by a current of one ampere.


3 How would you connect 10 [9V 20A] batteries to achieve a combined power output of 45V 100A?
66% Answer Correctly
series
series-parallel
perpendicular
orthogonal

Solution

Connecting the 10 batteries in series multiplies their voltage while keeping their current the same yielding a 90V 20A configuration. Connecting the 10 batteries in parallel multiplies their current while keeping their voltage the same yieleding a 9V 200A configuration. Using a series-parallel connection, 5 batteries can be connected in series and 5 can be connected in parallel resulting in a 45V 100A configuration.


4

The watt is a unit of measurement for:

78% Answer Correctly

frequency

resistance

energy

power


Solution

Electrical power is measured in watts (W) and is calculated by multiplying the voltage (V) applied to a circuit by the resulting current (I) that flows in the circuit: P = IV. In addition to measuring production capacity, power also measures the rate of energy consumption and many loads are rated for their consumption capacity. For example, a 60W lightbulb utilizes 60W of energy to produce the equivalent of 60W of heat and light energy.


5 How would you connect 8 [6V 5A] batteries to achieve a combined power output of 48V 5A?
53% Answer Correctly
parallel
perpendicular
series
series-parallel

Solution

Connecting the 8 batteries in series multiplies their voltage while keeping their current the same yielding a 48V 5A configuration. Connecting the 8 batteries in parallel multiplies their current while keeping their voltage the same yieleding a 6V 40A configuration. Using a series-parallel connection, 4 batteries can be connected in series and 4 can be connected in parallel resulting in a 24V 20A configuration.