ASVAB Electronics Information Practice Test 862039 Results

Your Results Global Average
Questions 5 5
Correct 0 3.57
Score 0% 71%

Review

1

Inductance is a factor in which of the following?

44% Answer Correctly

an AC circuit

batteries connected in serial

determining energy stored by a capacitor

a DC circuit


Solution

Inductance is a property of an AC circuit (or a component in an AC circuit) that quantifies resistance to changes in current. The current in an AC circuit is continuously changing and inductive reactance (the opposition to change) depends both on the inductance of the circuit or component and the rate at which the current is changing.


2

Longer the electrical wires mean _______________ voltage drop.

73% Answer Correctly

greater

lesser

complete

diminishing


Solution

Electrical wires have a certain amount of resistance per foot. A longer wire means more resistance and a greater voltage drop.


3 What's the overall power consumption of a piece of equipment that is rated for 8 amps at 70 volts?
80% Answer Correctly
1680 W
561.5 W
1120 W
560 W

Solution
Power is measured in watts (W) and 1 watt equals 1 ampere multiplied by 1 volt: P = \( V \times I \). For this problem, the equipment is rated for 8 amps (I) at 70 volts (V) so the equation becomes P = \( 70 \times 8 \) = 560 W

4 Use Ohm's Law to calculate the value of current in this circuit if voltage is 300 volts and resistance is 30 Ω.
81% Answer Correctly
5 A
15 A
10 A
16 A

Solution

Ohm's law specifies the relationship between voltage (V), current (I), and resistance (R) in an electrical circuit: V = IR.

Solved for current, I = \( \frac{V}{R} \) = \( \frac{300}{30} \) = 10 A


5

One of the lights on your Christmas tree burns out and this causes the rest of the lights connected to that strand to go dark. How are the lights in that strand connected?

73% Answer Correctly

perpendicular

parallel

series-parallel

series


Solution

Lights connected in series form a chain with each light connecting to adjacent lights via one wire. Therefore, if one of the lights burns out and breaks the series, none of the other lights will receive power and they'll go dark. Lights connected in parallel each connect to the positive and negative nodes of the power source and would not go dark if one of their neighbors burnt out.