ASVAB Electronics Information Practice Test 910124 Results

Your Results Global Average
Questions 5 5
Correct 0 3.28
Score 0% 66%

Review

1

This circuit component symbol represents a(n):

71% Answer Correctly

transistor

capacitor

diode

inductor


Solution

A diode allows current to pass easily in one direction and blocks current in the other direction. Diodes are commonly used for rectification which is the conversion of alternating current (AC) into direct current (DC). Because a diode only allows current flow in one direction, it will pass either the upper or lower half of AC waves (half-wave rectification) creating pulsating DC. Multiple diodes can be connected together to utilize both halves of the AC signal in full-wave rectification.


2

You would measure the amount of current through a circuit with a(n):

68% Answer Correctly

battery

ammeter

voltmeter

potentiometer


Solution

Current is the rate of flow of electrons per unit time and is measured in amperes (A). An ammeter is used to measure the electric current in a circuit.


3

Which of the following is not a purpose of a resistor in an electrical circuit?

70% Answer Correctly

multiply the current in the circuit

limit the current in the circuit

moderate the heat in the circuit

control the voltage in the circuit


Solution

Resistors can be chosen in a wide variety of values to control the voltage in a circuit, limit the current, or moderate the heat produced by the components in the circuit.


4

Electromotive force is another name for:

53% Answer Correctly

power

energy

current

voltage


Solution

Voltage (V) is the electrical potential difference between two points. Electrons will flow as current from areas of high potential (concentration of electrons) to areas of low potential. Voltage and current are directly proportional in that the higher the voltage applied to a conductor the higher the current that will result.


5 How would you connect 10 [9V 10A] batteries to achieve a combined power output of 45V 50A?
66% Answer Correctly
perpendicular
series-parallel
orthogonal
series

Solution

Connecting the 10 batteries in series multiplies their voltage while keeping their current the same yielding a 90V 10A configuration. Connecting the 10 batteries in parallel multiplies their current while keeping their voltage the same yieleding a 9V 100A configuration. Using a series-parallel connection, 5 batteries can be connected in series and 5 can be connected in parallel resulting in a 45V 50A configuration.