ASVAB Electronics Information Practice Test 96355 Results

	Your Results	Global Average
Questions	5	5
Correct	0	3.77
Score	0%	75%

Review

Which of the following is the formula for calculating electrical power?

73% Answer Correctly

	\(P = {V \over I}\)
	\(P = {I \over V}\)
	P = I²V
	P = IV

Solution

Electrical power is measured in watts (W) and is calculated by multiplying the voltage (V) applied to a circuit by the resulting current (I) that flows in the circuit: P = IV. In addition to measuring production capacity, power also measures the rate of energy consumption and many loads are rated for their consumption capacity. For example, a 60W lightbulb utilizes 60W of energy to produce the equivalent of 60W of heat and light energy.

The electrical potential difference between two points is called:

60% Answer Correctly

	conductance
	voltage
	current
	resistance

Solution

Voltage (V) is the electrical potential difference between two points. Electrons will flow as current from areas of high potential (concentration of electrons) to areas of low potential. Voltage and current are directly proportional in that the higher the voltage applied to a conductor the higher the current that will result.

3 What's the overall power consumption of a piece of equipment that is rated for 9 amps at 120 volts?

80% Answer Correctly

	1188 W
	1080 W
	1088 W
	1081.5 W

Solution

Power is measured in watts (W) and 1 watt equals 1 ampere multiplied by 1 volt: P = \( V \times I \). For this problem, the equipment is rated for 9 amps (I) at 120 volts (V) so the equation becomes P = \( 120 \times 9 \) = 1080 W

4 Use Ohm's Law to calculate the value of voltage in this circuit if resistance is 20 Ω and current is 5 amps.

85% Answer Correctly

	100 V
	110 V
	33.33 V
	102 V

Solution

Ohm's law specifies the relationship between voltage (V), current (I), and resistance (R) in an electrical circuit: V = IR.

V = \( I \times R \) = \( 5 \times 20 \) = 100 V

Which of the following statements about a capacitor is false?

77% Answer Correctly

	you should always discharge any capacitors before working on an electronic circuit
	to discharge a capacitor safely, use a high-wattage resistor comparable to the capacitance of the capacitor
	a capacitor remains charged even after the input voltage is removed
	it is safe to touch a capacitor with your hands as long as it is small

Solution

The purpose of a capacitor is to retain electric charge and it will do so even after its input voltage is removed. After the input voltage is removed, the capacitor will slowly discharge but, depending on the size and characteristics of the capacitor, discharging could take from a few minutes to a few years. So, it's never safe to touch a capacitor with your hands and you should make sure to discharge any capacitors in a circuit before working on it using an appropriately high-wattage resistor or a capacitor discharge tool.