ASVAB Electronics Information Practice Test 99773 Results

Your Results Global Average
Questions 5 5
Correct 0 3.82
Score 0% 76%

Review

1 Use Ohm's Law to calculate the value of current in this circuit if voltage is 140 volts and resistance is 40 Ω.
81% Answer Correctly
1.17 A
3.5 A
5.5 A
3.85 A

Solution

Ohm's law specifies the relationship between voltage (V), current (I), and resistance (R) in an electrical circuit: V = IR.

Solved for current, I = \( \frac{V}{R} \) = \( \frac{140}{40} \) = 3.5 A


2

Using a fuse with a current rating higher than that required by a circuit:

70% Answer Correctly

is required

is recommended

makes the circuit less safe

makes no difference


Solution

A fuse is a type of low resistance resistor that stops current flow in a circuit in response to a larger than intended electric current flow. Using a fuse with a higher current rating than required by a circuit is less safe as it could potentially allow overcurrent and risk a fire or heat-related equipment damage.


3

The ohm is a unit of measurement for:

81% Answer Correctly

energy

power

capacitance

resistance


Solution

Resistance is opposition to the flow of current and is measured in ohms (Ω). One ohm is defined as the amount of resistance that will allow one ampere of current to flow if one volt of voltage is applied. As resistance increases, current decreases as resistance and current are inversely proportional.


4

The hertz is a unit of measurement for:

81% Answer Correctly

inductance

energy

frequency

power


Solution

The hertz is a unit of measurement for frequency.


5

Which of the following allows current to pass easily in one direction and blocks current in the other direction?

69% Answer Correctly

capacitor

resistor

diode

inductor


Solution

A diode allows current to pass easily in one direction and blocks current in the other direction. Diodes are commonly used for rectification which is the conversion of alternating current (AC) into direct current (DC). Because a diode only allows current flow in one direction, it will pass either the upper or lower half of AC waves (half-wave rectification) creating pulsating DC. Multiple diodes can be connected together to utilize both halves of the AC signal in full-wave rectification.