ASVAB Electronics Information Electron Flow Practice Test 141552 Results
Your Results
Global Average
Questions
5
5
Correct
0
4.59
Score
0%
92%
Review
1
What's the overall power consumption of a piece of equipment that is rated for 3 amps at 100 volts?
92%
Answer Correctly
301 W
100 W
300 W
330 W
Solution
Power is measured in watts (W) and 1 watt equals 1 ampere multiplied by 1 volt: P = \( V \times I \). For this problem, the equipment is rated for 3 amps (I) at 100 volts (V) so the equation becomes P = \( 100 \times 3 \) = 300 W
2
What's the overall power consumption of a piece of equipment that is rated for 3 amps at 100 volts?
92%
Answer Correctly
301 W
100 W
300 W
330 W
Solution
Power is measured in watts (W) and 1 watt equals 1 ampere multiplied by 1 volt: P = \( V \times I \). For this problem, the equipment is rated for 3 amps (I) at 100 volts (V) so the equation becomes P = \( 100 \times 3 \) = 300 W
3
What's the overall power consumption of a piece of equipment that is rated for 3 amps at 100 volts?
92%
Answer Correctly
301 W
100 W
300 W
330 W
Solution
Power is measured in watts (W) and 1 watt equals 1 ampere multiplied by 1 volt: P = \( V \times I \). For this problem, the equipment is rated for 3 amps (I) at 100 volts (V) so the equation becomes P = \( 100 \times 3 \) = 300 W
4
What's the overall power consumption of a piece of equipment that is rated for 3 amps at 100 volts?
92%
Answer Correctly
301 W
100 W
300 W
330 W
Solution
Power is measured in watts (W) and 1 watt equals 1 ampere multiplied by 1 volt: P = \( V \times I \). For this problem, the equipment is rated for 3 amps (I) at 100 volts (V) so the equation becomes P = \( 100 \times 3 \) = 300 W
5
What's the overall power consumption of a piece of equipment that is rated for 3 amps at 100 volts?
92%
Answer Correctly
301 W
100 W
300 W
330 W
Solution
Power is measured in watts (W) and 1 watt equals 1 ampere multiplied by 1 volt: P = \( V \times I \). For this problem, the equipment is rated for 3 amps (I) at 100 volts (V) so the equation becomes P = \( 100 \times 3 \) = 300 W