ASVAB Electronics Information Electron Flow Practice Test 141552 Results

Your Results Global Average
Questions 5 5
Correct 0 4.59
Score 0% 92%

Review

1 What's the overall power consumption of a piece of equipment that is rated for 3 amps at 100 volts?
92% Answer Correctly
301 W
100 W
300 W
330 W

Solution
Power is measured in watts (W) and 1 watt equals 1 ampere multiplied by 1 volt: P = \( V \times I \). For this problem, the equipment is rated for 3 amps (I) at 100 volts (V) so the equation becomes P = \( 100 \times 3 \) = 300 W

2 What's the overall power consumption of a piece of equipment that is rated for 3 amps at 100 volts?
92% Answer Correctly
301 W
100 W
300 W
330 W

Solution
Power is measured in watts (W) and 1 watt equals 1 ampere multiplied by 1 volt: P = \( V \times I \). For this problem, the equipment is rated for 3 amps (I) at 100 volts (V) so the equation becomes P = \( 100 \times 3 \) = 300 W

3 What's the overall power consumption of a piece of equipment that is rated for 3 amps at 100 volts?
92% Answer Correctly
301 W
100 W
300 W
330 W

Solution
Power is measured in watts (W) and 1 watt equals 1 ampere multiplied by 1 volt: P = \( V \times I \). For this problem, the equipment is rated for 3 amps (I) at 100 volts (V) so the equation becomes P = \( 100 \times 3 \) = 300 W

4 What's the overall power consumption of a piece of equipment that is rated for 3 amps at 100 volts?
92% Answer Correctly
301 W
100 W
300 W
330 W

Solution
Power is measured in watts (W) and 1 watt equals 1 ampere multiplied by 1 volt: P = \( V \times I \). For this problem, the equipment is rated for 3 amps (I) at 100 volts (V) so the equation becomes P = \( 100 \times 3 \) = 300 W

5 What's the overall power consumption of a piece of equipment that is rated for 3 amps at 100 volts?
92% Answer Correctly
301 W
100 W
300 W
330 W

Solution
Power is measured in watts (W) and 1 watt equals 1 ampere multiplied by 1 volt: P = \( V \times I \). For this problem, the equipment is rated for 3 amps (I) at 100 volts (V) so the equation becomes P = \( 100 \times 3 \) = 300 W