ASVAB Electronics Information Electron Flow Practice Test 835032 Results

Your Results Global Average
Questions 5 5
Correct 0 4.59
Score 0% 92%

Review

1 What's the overall power consumption of a piece of equipment that is rated for 3 amps at 150 volts?
92% Answer Correctly
495 W
225 W
675 W
450 W

Solution
Power is measured in watts (W) and 1 watt equals 1 ampere multiplied by 1 volt: P = \( V \times I \). For this problem, the equipment is rated for 3 amps (I) at 150 volts (V) so the equation becomes P = \( 150 \times 3 \) = 450 W

2 What's the overall power consumption of a piece of equipment that is rated for 3 amps at 150 volts?
92% Answer Correctly
495 W
225 W
675 W
450 W

Solution
Power is measured in watts (W) and 1 watt equals 1 ampere multiplied by 1 volt: P = \( V \times I \). For this problem, the equipment is rated for 3 amps (I) at 150 volts (V) so the equation becomes P = \( 150 \times 3 \) = 450 W

3 What's the overall power consumption of a piece of equipment that is rated for 3 amps at 150 volts?
92% Answer Correctly
495 W
225 W
675 W
450 W

Solution
Power is measured in watts (W) and 1 watt equals 1 ampere multiplied by 1 volt: P = \( V \times I \). For this problem, the equipment is rated for 3 amps (I) at 150 volts (V) so the equation becomes P = \( 150 \times 3 \) = 450 W

4 What's the overall power consumption of a piece of equipment that is rated for 3 amps at 150 volts?
92% Answer Correctly
495 W
225 W
675 W
450 W

Solution
Power is measured in watts (W) and 1 watt equals 1 ampere multiplied by 1 volt: P = \( V \times I \). For this problem, the equipment is rated for 3 amps (I) at 150 volts (V) so the equation becomes P = \( 150 \times 3 \) = 450 W

5 What's the overall power consumption of a piece of equipment that is rated for 3 amps at 150 volts?
92% Answer Correctly
495 W
225 W
675 W
450 W

Solution
Power is measured in watts (W) and 1 watt equals 1 ampere multiplied by 1 volt: P = \( V \times I \). For this problem, the equipment is rated for 3 amps (I) at 150 volts (V) so the equation becomes P = \( 150 \times 3 \) = 450 W