ASVAB Electronics Information Electron Flow Practice Test 878794 Results

Your Results Global Average
Questions 5 5
Correct 0 4.60
Score 0% 92%

Review

1 What's the overall power consumption of a piece of equipment that is rated for 2 amps at 150 volts?
92% Answer Correctly
900 W
300 W
301.5 W
302 W
Solution
Power is measured in watts (W) and 1 watt equals 1 ampere multiplied by 1 volt: P = \( V \times I \). For this problem, the equipment is rated for 2 amps (I) at 150 volts (V) so the equation becomes P = \( 150 \times 2 \) = 300 W
2 What's the overall power consumption of a piece of equipment that is rated for 2 amps at 150 volts?
92% Answer Correctly
900 W
300 W
301.5 W
302 W
Solution
Power is measured in watts (W) and 1 watt equals 1 ampere multiplied by 1 volt: P = \( V \times I \). For this problem, the equipment is rated for 2 amps (I) at 150 volts (V) so the equation becomes P = \( 150 \times 2 \) = 300 W
3 What's the overall power consumption of a piece of equipment that is rated for 2 amps at 150 volts?
92% Answer Correctly
900 W
300 W
301.5 W
302 W
Solution
Power is measured in watts (W) and 1 watt equals 1 ampere multiplied by 1 volt: P = \( V \times I \). For this problem, the equipment is rated for 2 amps (I) at 150 volts (V) so the equation becomes P = \( 150 \times 2 \) = 300 W
4 What's the overall power consumption of a piece of equipment that is rated for 2 amps at 150 volts?
92% Answer Correctly
900 W
300 W
301.5 W
302 W
Solution
Power is measured in watts (W) and 1 watt equals 1 ampere multiplied by 1 volt: P = \( V \times I \). For this problem, the equipment is rated for 2 amps (I) at 150 volts (V) so the equation becomes P = \( 150 \times 2 \) = 300 W
5 What's the overall power consumption of a piece of equipment that is rated for 2 amps at 150 volts?
92% Answer Correctly
900 W
300 W
301.5 W
302 W
Solution
Power is measured in watts (W) and 1 watt equals 1 ampere multiplied by 1 volt: P = \( V \times I \). For this problem, the equipment is rated for 2 amps (I) at 150 volts (V) so the equation becomes P = \( 150 \times 2 \) = 300 W