ASVAB Electronics Information Electron Flow Practice Test 982335 Results
Your Results
Global Average
Questions
5
5
Correct
0
4.60
Score
0%
92%
Review
1
What's the overall power consumption of a piece of equipment that is rated for 6 amps at 120 volts?
92%
Answer Correctly
648 W
721.5 W
720 W
360 W
Solution
Power is measured in watts (W) and 1 watt equals 1 ampere multiplied by 1 volt: P = \( V \times I \). For this problem, the equipment is rated for 6 amps (I) at 120 volts (V) so the equation becomes P = \( 120 \times 6 \) = 720 W
2
What's the overall power consumption of a piece of equipment that is rated for 6 amps at 120 volts?
92%
Answer Correctly
648 W
721.5 W
720 W
360 W
Solution
Power is measured in watts (W) and 1 watt equals 1 ampere multiplied by 1 volt: P = \( V \times I \). For this problem, the equipment is rated for 6 amps (I) at 120 volts (V) so the equation becomes P = \( 120 \times 6 \) = 720 W
3
What's the overall power consumption of a piece of equipment that is rated for 6 amps at 120 volts?
92%
Answer Correctly
648 W
721.5 W
720 W
360 W
Solution
Power is measured in watts (W) and 1 watt equals 1 ampere multiplied by 1 volt: P = \( V \times I \). For this problem, the equipment is rated for 6 amps (I) at 120 volts (V) so the equation becomes P = \( 120 \times 6 \) = 720 W
4
What's the overall power consumption of a piece of equipment that is rated for 6 amps at 120 volts?
92%
Answer Correctly
648 W
721.5 W
720 W
360 W
Solution
Power is measured in watts (W) and 1 watt equals 1 ampere multiplied by 1 volt: P = \( V \times I \). For this problem, the equipment is rated for 6 amps (I) at 120 volts (V) so the equation becomes P = \( 120 \times 6 \) = 720 W
5
What's the overall power consumption of a piece of equipment that is rated for 6 amps at 120 volts?
92%
Answer Correctly
648 W
721.5 W
720 W
360 W
Solution
Power is measured in watts (W) and 1 watt equals 1 ampere multiplied by 1 volt: P = \( V \times I \). For this problem, the equipment is rated for 6 amps (I) at 120 volts (V) so the equation becomes P = \( 120 \times 6 \) = 720 W