ASVAB Electronics Information Electron Flow Practice Test 982335 Results

Your Results Global Average
Questions 5 5
Correct 0 4.60
Score 0% 92%

Review

1 What's the overall power consumption of a piece of equipment that is rated for 6 amps at 120 volts?
92% Answer Correctly
648 W
721.5 W
720 W
360 W

Solution
Power is measured in watts (W) and 1 watt equals 1 ampere multiplied by 1 volt: P = \( V \times I \). For this problem, the equipment is rated for 6 amps (I) at 120 volts (V) so the equation becomes P = \( 120 \times 6 \) = 720 W

2 What's the overall power consumption of a piece of equipment that is rated for 6 amps at 120 volts?
92% Answer Correctly
648 W
721.5 W
720 W
360 W

Solution
Power is measured in watts (W) and 1 watt equals 1 ampere multiplied by 1 volt: P = \( V \times I \). For this problem, the equipment is rated for 6 amps (I) at 120 volts (V) so the equation becomes P = \( 120 \times 6 \) = 720 W

3 What's the overall power consumption of a piece of equipment that is rated for 6 amps at 120 volts?
92% Answer Correctly
648 W
721.5 W
720 W
360 W

Solution
Power is measured in watts (W) and 1 watt equals 1 ampere multiplied by 1 volt: P = \( V \times I \). For this problem, the equipment is rated for 6 amps (I) at 120 volts (V) so the equation becomes P = \( 120 \times 6 \) = 720 W

4 What's the overall power consumption of a piece of equipment that is rated for 6 amps at 120 volts?
92% Answer Correctly
648 W
721.5 W
720 W
360 W

Solution
Power is measured in watts (W) and 1 watt equals 1 ampere multiplied by 1 volt: P = \( V \times I \). For this problem, the equipment is rated for 6 amps (I) at 120 volts (V) so the equation becomes P = \( 120 \times 6 \) = 720 W

5 What's the overall power consumption of a piece of equipment that is rated for 6 amps at 120 volts?
92% Answer Correctly
648 W
721.5 W
720 W
360 W

Solution
Power is measured in watts (W) and 1 watt equals 1 ampere multiplied by 1 volt: P = \( V \times I \). For this problem, the equipment is rated for 6 amps (I) at 120 volts (V) so the equation becomes P = \( 120 \times 6 \) = 720 W