| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 3.31 |
| Score | 0% | 66% |
| 229.5 V | |
| 255 V | |
| 280.5 V | |
| 257 V |
Ohm's law specifies the relationship between voltage (V), current (I), and resistance (R) in an electrical circuit: V = IR.
V = \( I \times R \) = \( 8.5 \times 30 \) = 255 V
| perpendicular | |
| parallel | |
| orthogonal | |
| series-parallel |
Connecting the 6 batteries in series multiplies their voltage while keeping their current the same yielding a 54V 20A configuration. Connecting the 6 batteries in parallel multiplies their current while keeping their voltage the same yieleding a 9V 120A configuration. Using a series-parallel connection, 3 batteries can be connected in series and 3 can be connected in parallel resulting in a 27V 60A configuration.
| perpendicular | |
| parallel | |
| series-parallel | |
| series |
Connecting the 8 batteries in series multiplies their voltage while keeping their current the same yielding a 96V 25A configuration. Connecting the 8 batteries in parallel multiplies their current while keeping their voltage the same yieleding a 12V 200A configuration. Using a series-parallel connection, 4 batteries can be connected in series and 4 can be connected in parallel resulting in a 48V 100A configuration.
| 10 Ω | |
| 13 Ω | |
| 3 Ω | |
| 12 Ω |
Ohm's law specifies the relationship between voltage (V), current (I), and resistance (R) in an electrical circuit: V = IR.
Solved for resistance, R = \( \frac{V}{I} \) = \( \frac{30}{3} \) = 10 Ω
| 45V 125A | |
| 9V 250A | |
| 90V 25A | |
| 90V 250A |
Connecting the 10 batteries in series multiplies their voltage while keeping their current the same yielding a 90V 25A configuration. Connecting the 10 batteries in parallel multiplies their current while keeping their voltage the same yielding a 9V 250A configuration. Using a series-parallel connection, 5 batteries can be connected in series and 5 can be connected in parallel resulting in a 45V 125A configuration.