ASVAB Electronics Information Circuits Practice Test 65113 Results

Your Results Global Average
Questions 5 5
Correct 0 3.31
Score 0% 66%

Review

1 Use Ohm's Law to calculate the value of voltage in this circuit if resistance is 30 Ω and current is 8.5 amps.
85% Answer Correctly
229.5 V
255 V
280.5 V
257 V

Solution

Ohm's law specifies the relationship between voltage (V), current (I), and resistance (R) in an electrical circuit: V = IR.

V = \( I \times R \) = \( 8.5 \times 30 \) = 255 V


2 How would you connect 6 [9V 20A] batteries to achieve a combined power output of 27V 60A?
67% Answer Correctly
perpendicular
parallel
orthogonal
series-parallel

Solution

Connecting the 6 batteries in series multiplies their voltage while keeping their current the same yielding a 54V 20A configuration. Connecting the 6 batteries in parallel multiplies their current while keeping their voltage the same yieleding a 9V 120A configuration. Using a series-parallel connection, 3 batteries can be connected in series and 3 can be connected in parallel resulting in a 27V 60A configuration.


3 How would you connect 8 [12V 25A] batteries to achieve a combined power output of 96V 25A?
53% Answer Correctly
perpendicular
parallel
series-parallel
series

Solution

Connecting the 8 batteries in series multiplies their voltage while keeping their current the same yielding a 96V 25A configuration. Connecting the 8 batteries in parallel multiplies their current while keeping their voltage the same yieleding a 12V 200A configuration. Using a series-parallel connection, 4 batteries can be connected in series and 4 can be connected in parallel resulting in a 48V 100A configuration.


4 Use Ohm's Law to calculate the value of resistance in this circuit if voltage is 30 volts and current is 3 amps.
81% Answer Correctly
10 Ω
13 Ω
3 Ω
12 Ω

Solution

Ohm's law specifies the relationship between voltage (V), current (I), and resistance (R) in an electrical circuit: V = IR.

Solved for resistance, R = \( \frac{V}{I} \) = \( \frac{30}{3} \) = 10 Ω


5 Suppose you have 10 [9V 25A] batteries that you can connect together in series, in parallel, or in series-parallel. Which of the following voltage and ampere combinations cannot be attained using these 10 batteries?
46% Answer Correctly
45V 125A
9V 250A
90V 25A
90V 250A

Solution

Connecting the 10 batteries in series multiplies their voltage while keeping their current the same yielding a 90V 25A configuration. Connecting the 10 batteries in parallel multiplies their current while keeping their voltage the same yielding a 9V 250A configuration. Using a series-parallel connection, 5 batteries can be connected in series and 5 can be connected in parallel resulting in a 45V 125A configuration.