ASVAB Electronics Information Electronic Components Practice Test 495256 Results

ASVAB Electronics Information Electronic Components Practice Test 495256 Results

	Your Results	Global Average
Questions	5	5
Correct	0	4.19
Score	0%	84%

Review

1 A circuit with a 120-volt power supply is protected by a 25-amp circuit breaker. What is the largest number of watts loads on this circuit can safely use?

84% Answer Correctly

	3001.5 W
	3300 W
	3000 W
	2999 W

Solution

Wattage is current multiplied by voltage: W = IV. So, the maximum amount of power a 120-volt circuit with a 25A circuit breaker would allow is 120V x 25A = 3000 W.

2 A circuit with a 120-volt power supply is protected by a 25-amp circuit breaker. What is the largest number of watts loads on this circuit can safely use?

84% Answer Correctly

	3001.5 W
	3300 W
	3000 W
	2999 W

Solution

Wattage is current multiplied by voltage: W = IV. So, the maximum amount of power a 120-volt circuit with a 25A circuit breaker would allow is 120V x 25A = 3000 W.

3 A circuit with a 120-volt power supply is protected by a 25-amp circuit breaker. What is the largest number of watts loads on this circuit can safely use?

84% Answer Correctly

	3001.5 W
	3300 W
	3000 W
	2999 W

Solution

Wattage is current multiplied by voltage: W = IV. So, the maximum amount of power a 120-volt circuit with a 25A circuit breaker would allow is 120V x 25A = 3000 W.

4 A circuit with a 120-volt power supply is protected by a 25-amp circuit breaker. What is the largest number of watts loads on this circuit can safely use?

84% Answer Correctly

	3001.5 W
	3300 W
	3000 W
	2999 W

Solution

Wattage is current multiplied by voltage: W = IV. So, the maximum amount of power a 120-volt circuit with a 25A circuit breaker would allow is 120V x 25A = 3000 W.

5 A circuit with a 120-volt power supply is protected by a 25-amp circuit breaker. What is the largest number of watts loads on this circuit can safely use?

84% Answer Correctly

	3001.5 W
	3300 W
	3000 W
	2999 W

Solution

Wattage is current multiplied by voltage: W = IV. So, the maximum amount of power a 120-volt circuit with a 25A circuit breaker would allow is 120V x 25A = 3000 W.