ASVAB General Science Practice Test 26111 Results

Your Results Global Average
Questions 5 5
Correct 0 3.51
Score 0% 70%

Review

1

A large naturally occurring community of flora and fauna occupying a major habitat is:

75% Answer Correctly

a population

a biome

a food chain

a community


Solution

A biome is a large naturally occurring community of flora (plants) and fauna (animals) occupying a major habitat (home or environment).


2

The universal recipient blood type can recieve any other blood type. Which blood type is the universal recipient?

45% Answer Correctly

AB-positive

O-negative

AB

O


Solution

Blood transfer is limited by the type and Rh factor of the blood. Someone who has Rh-factor negative blood cannot receive blood with a positive type but a person with Rh-factor positive type blood can receive Rh-negative blood. Type O negative blood is the universal donor because it can be given to a person with any blood type. Type AB positive is the universal recipient meaning someone with this blood type can receive any other type of blood.


3

Traits represented by genes may be which of the following?

82% Answer Correctly

expressed

recessive

all of these

dominant


Solution

The traits represented by genes are inherited independently of each other  (one from the male and one from the female gamete) and a trait can be dominant or recessive.  A dominant trait will be expressed when paired with a recessive trait while two copies of a recessive trait (one from each parent) must be present for the recessive trait to be expressed.


4

In the food chain, consumers are classified as which of the following?

73% Answer Correctly

primary

secondary

tertiary

all of these


Solution

Most animals consume other organisms to survive. Consumers (heterotrophs) are divided into three types, primary, secondary, and tertiary, based on their place in the food chain.


5

212°F is how many °C?

77% Answer Correctly

0

-100

100

\(135 {5 \over 9}\)


Solution

The formula to convert from F° to C° is:

\(C° = {5 \over 9} (F° - 32)\)

plugging in our values gives:

\(C° = {5 \over 9} (212 - 32)\)

\(C° = {5 \over 9} (180) = {{180 \times 5} \over 9}\)

\(C° = {900 \over 9}\)

\(C° = 100\)