ASVAB General Science Practice Test 359633 Results

Your Results Global Average
Questions 5 5
Correct 0 2.72
Score 0% 54%

Review

1

A transition zone between two air masses is called:

70% Answer Correctly

fog

boundary

front

thunderstorm


Solution

An air mass is a large body of air that has similar moisture (density) and temperature characteristics. A front is a transition zone between two air masses.


2

Which of the following substances gives up positively charged hydrogen ions (H+) when dissolved in water?

55% Answer Correctly

base

alkaline

acid

solution


Solution

An acid is a substance that gives up positively charged hydrogen ions (H+) when dissolved in water. A base (alkaline) gives up negatively charged hydroxide ions (OH-) when dissolved in water. pH is a scale that measures of how basic or acidic a solution is. Numbered from 0 to 14, solutions with a pH of 7 are neutral, less than 7 are acidic, more than 7 are alkaline.


3

Which of the following substances gives up negatively charged hydroxide ions (OH-) when dissolved in water?

42% Answer Correctly

acid

ion

base

hydrogen


Solution

An acid is a substance that gives up positively charged hydrogen ions (H+) when dissolved in water. A base (alkaline) gives up negatively charged hydroxide ions (OH-) when dissolved in water. pH is a scale that measures of how basic or acidic a solution is. Numbered from 0 to 14, solutions with a pH of 7 are neutral, less than 7 are acidic, more than 7 are alkaline.


4

What kind of weather front is likely to create clouds and storms?

58% Answer Correctly

warm front

temperate front

cold front 

stationary front


Solution

A warm front is the boundary between warm and cool (or cold) air when the warm air is replacing the cold air. Warm air at the surface pushes above the cool air mass creating clouds and storms.


5

Which of the following is the formula for work?

47% Answer Correctly

\(W = {\vec{F} \over \vec{d} }\)

\(W = \vec{F}\vec{d}\)

\(W = {F}{d}\)

\(W = {{F}\over{d}}\)


Solution

Work is performed on an object when an applied force causes displacement along the same vector. Measured in joules (J) or newton-meter (Nm), work is calculated by multiplying force times displacement:  \(W = \vec{F}\vec{d}\)