ASVAB General Science Practice Test 586319 Results

Your Results Global Average
Questions 5 5
Correct 0 3.62
Score 0% 72%

Review

1

An air mass is a large body of air that has which of the following characteristics?

87% Answer Correctly

similar density

similar moisture

all of these

similar temperature


Solution

An air mass is a large body of air that has similar moisture (density) and temperature characteristics. A front is a transition zone between two air masses.


2

"The acceleration of an object as produced by a net force is directly proportional to the magnitude of the net force, in the same direction as the net force, and inversely proportional to the mass of the object." This describes which of Newton's laws of motion?

65% Answer Correctly

fourth

second

first

third


Solution

Newton's second law of motion states that The acceleration of an object as produced by a net force is directly proportional to the magnitude of the net force, in the same direction as the net force, and inversely proportional to the mass of the object. This law basically means that the greater the mass of an object, the more force is needed to overcome its inertia.


3

Which of the following represents the largest value?

61% Answer Correctly

1 kL

1 ML

1 cL

1 mL


Solution

Mega (M) is 106, kilo (k) is 103, centi (c) is 10-2, milli (m) is 10-3 so 1 ML represents the largest value.


4

Plant cells may generate energy through which of the following?

73% Answer Correctly

anaerobic respiration

all of these

photosynthesis

aerobic respiration


Solution

Some plant cells produce their own energy through photosynthesis which is the process by which sunlight, carbon dioxide, and water react to make sugar and oxygen. Animal cells cannot produce their own energy and, instead, generate energy when mitochondria consume outside sugar and oxygen through aerobic respiration.


5

212°F is how many °C?

77% Answer Correctly

\(135 {5 \over 9}\)

-100

100

0


Solution

The formula to convert from F° to C° is:

\(C° = {5 \over 9} (F° - 32)\)

plugging in our values gives:

\(C° = {5 \over 9} (212 - 32)\)

\(C° = {5 \over 9} (180) = {{180 \times 5} \over 9}\)

\(C° = {900 \over 9}\)

\(C° = 100\)