When solving an equation with two variables, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)
Solve -5c - 4c = -4c + 8z + 6 for c in terms of z.
| 15z - 1 | |
| -5z + \(\frac{2}{3}\) | |
| -12z - 6 | |
| -\(\frac{3}{5}\)z + 1 |