ASVAB Math Knowledge Practice Test 102686

Question 5 of 5
Two Variables

When solving an equation with two variables, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)

Solve -9a + 3a = a - z + 6 for a in terms of z.

-\(\frac{1}{2}\)z + 1\(\frac{1}{8}\)
-\(\frac{1}{2}\)z - 4\(\frac{1}{2}\)
\(\frac{1}{6}\)z + \(\frac{1}{4}\)
\(\frac{2}{5}\)z - \(\frac{3}{5}\)