| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 2.63 |
| Score | 0% | 53% |
Breaking apart a quadratic expression into a pair of binomials is called:
squaring |
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deconstructing |
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normalizing |
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factoring |
To factor a quadratic expression, apply the FOIL (First, Outside, Inside, Last) method in reverse.
Which of the following statements about parallel lines with a transversal is not correct?
all of the angles formed by a transversal are called interior angles |
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angles in the same position on different parallel lines are called corresponding angles |
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all acute angles equal each other |
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same-side interior angles are complementary and equal each other |
Parallel lines are lines that share the same slope (steepness) and therefore never intersect. A transversal occurs when a set of parallel lines are crossed by another line. All of the angles formed by a transversal are called interior angles and angles in the same position on different parallel lines equal each other (a° = w°, b° = x°, c° = z°, d° = y°) and are called corresponding angles. Alternate interior angles are equal (a° = z°, b° = y°, c° = w°, d° = x°) and all acute angles (a° = c° = w° = z°) and all obtuse angles (b° = d° = x° = y°) equal each other. Same-side interior angles are supplementary and add up to 180° (e.g. a° + d° = 180°, d° + c° = 180°).
A trapezoid is a quadrilateral with one set of __________ sides.
parallel |
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equal angle |
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equal length |
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right angle |
A trapezoid is a quadrilateral with one set of parallel sides.
For this diagram, the Pythagorean theorem states that b2 = ?
c2 + a2 |
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c2 - a2 |
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c - a |
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a2 - c2 |
The Pythagorean theorem defines the relationship between the side lengths of a right triangle. The length of the hypotenuse squared (c2) is equal to the sum of the two perpendicular sides squared (a2 + b2): c2 = a2 + b2 or, solved for c, \(c = \sqrt{a + b}\)
Solve -3a + 10a = 5a - 9z - 9 for a in terms of z.
| 2\(\frac{1}{3}\)z + \(\frac{2}{3}\) | |
| 2\(\frac{3}{8}\)z + 1\(\frac{1}{8}\) | |
| -1\(\frac{3}{5}\)z + 1\(\frac{2}{5}\) | |
| -1\(\frac{1}{2}\)z + 3 |
To solve this equation, isolate the variable for which you are solving (a) on one side of the equation and put everything else on the other side.
-3a + 10z = 5a - 9z - 9
-3a = 5a - 9z - 9 - 10z
-3a - 5a = -9z - 9 - 10z
-8a = -19z - 9
a = \( \frac{-19z - 9}{-8} \)
a = \( \frac{-19z}{-8} \) + \( \frac{-9}{-8} \)
a = 2\(\frac{3}{8}\)z + 1\(\frac{1}{8}\)