ASVAB Math Knowledge Practice Test 103711

Question 5 of 5
Two Variables

When solving an equation with two variables, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)

Solve 3c + 6c = -2c - 7z - 2 for c in terms of z.

-2\(\frac{5}{6}\)z + \(\frac{2}{3}\)
-2\(\frac{3}{5}\)z - \(\frac{2}{5}\)
2\(\frac{2}{7}\)z - \(\frac{5}{7}\)
-6z - 2\(\frac{1}{2}\)