ASVAB Math Knowledge Practice Test 103938

Question 2 of 5
Two Variables

When solving an equation with two variables, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)

Solve 5a + 5a = 3a + 2z - 3 for a in terms of z.

-1\(\frac{1}{2}\)z - 1\(\frac{1}{2}\)
-\(\frac{1}{15}\)z + \(\frac{4}{15}\)
-\(\frac{3}{14}\)z - \(\frac{1}{14}\)
-9z - 6