ASVAB Math Knowledge Practice Test 10471 Results

Your Results Global Average
Questions 5 5
Correct 0 2.62
Score 0% 52%

Review

1

Factor y2 + 16y + 64

54% Answer Correctly
(y - 8)(y + 8)
(y - 8)(y - 8)
(y + 8)(y + 8)
(y + 8)(y - 8)

Solution

To factor a quadratic expression, apply the FOIL method (First, Outside, Inside, Last) in reverse. First, find the two Last terms that will multiply to produce 64 as well and sum (Inside, Outside) to equal 16. For this problem, those two numbers are 8 and 8. Then, plug these into a set of binomials using the square root of the First variable (y2):

y2 + 16y + 64
y2 + (8 + 8)y + (8 x 8)
(y + 8)(y + 8)


2

Find the value of a:
a + x = 5
-3a - 9x = 8

42% Answer Correctly
\(\frac{23}{51}\)
9\(\frac{1}{4}\)
\(\frac{7}{37}\)
8\(\frac{5}{6}\)

Solution

You need to find the value of a so solve the first equation in terms of x:

a + x = 5
x = 5 - a

then substitute the result (5 - 1a) into the second equation:

-3a - 9(5 - a) = 8
-3a + (-9 x 5) + (-9 x -a) = 8
-3a - 45 + 9a = 8
-3a + 9a = 8 + 45
6a = 53
a = \( \frac{53}{6} \)
a = 8\(\frac{5}{6}\)


3

What is the circumference of a circle with a radius of 5?

71% Answer Correctly
14π
10π
18π
26π

Solution

The formula for circumference is circle diameter x π. Circle diameter is 2 x radius:

c = πd
c = π(2 * r)
c = π(2 * 5)
c = 10π


4

On this circle, a line segment connecting point A to point D is called:

46% Answer Correctly

chord

diameter

radius

circumference


Solution

A circle is a figure in which each point around its perimeter is an equal distance from the center. The radius of a circle is the distance between the center and any point along its perimeter. A chord is a line segment that connects any two points along its perimeter. The diameter of a circle is the length of a chord that passes through the center of the circle and equals twice the circle's radius (2r).


5

The dimensions of this cylinder are height (h) = 2 and radius (r) = 7. What is the surface area?

48% Answer Correctly
216π
126π
112π
240π

Solution

The surface area of a cylinder is 2πr2 + 2πrh:

sa = 2πr2 + 2πrh
sa = 2π(72) + 2π(7 x 2)
sa = 2π(49) + 2π(14)
sa = (2 x 49)π + (2 x 14)π
sa = 98π + 28π
sa = 126π