ASVAB Math Knowledge Practice Test 105406

Question 3 of 5
Two Variables

When solving an equation with two variables, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)

Solve 2b + 6b = 8b - y - 2 for b in terms of y.

1\(\frac{1}{6}\)y + \(\frac{1}{3}\)
y - \(\frac{4}{9}\)
\(\frac{3}{4}\)y - \(\frac{1}{2}\)
-1\(\frac{1}{4}\)y - 1\(\frac{3}{4}\)