When solving an equation with two variables, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)
Solve 2c - 4c = -4c + 8z + 5 for c in terms of z.
| -\(\frac{3}{5}\)z - \(\frac{3}{5}\) | |
| 1\(\frac{2}{9}\)z - \(\frac{5}{9}\) | |
| 2z + \(\frac{5}{6}\) | |
| -8z - 4 |