| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 3.09 |
| Score | 0% | 62% |
This diagram represents two parallel lines with a transversal. If z° = 30, what is the value of w°?
| 156 | |
| 160 | |
| 30 | |
| 161 |
For parallel lines with a transversal, the following relationships apply:
Applying these relationships starting with z° = 30, the value of w° is 30.
The dimensions of this cylinder are height (h) = 7 and radius (r) = 8. What is the volume?
| 448π | |
| 45π | |
| 3π | |
| 80π |
The volume of a cylinder is πr2h:
v = πr2h
v = π(82 x 7)
v = 448π
Solve for x:
-4x - 7 > \( \frac{x}{4} \)
| x > -\(\frac{10}{17}\) | |
| x > \(\frac{10}{31}\) | |
| x > -1\(\frac{11}{17}\) | |
| x > 1\(\frac{1}{5}\) |
To solve this equation, repeatedly do the same thing to both sides of the equation until the variable is isolated on one side of the > sign and the answer on the other.
-4x - 7 > \( \frac{x}{4} \)
4 x (-4x - 7) > x
(4 x -4x) + (4 x -7) > x
-16x - 28 > x
-16x - 28 - x > 0
-16x - x > 28
-17x > 28
x > \( \frac{28}{-17} \)
x > -1\(\frac{11}{17}\)
Solve for y:
y2 + 22y + 67 = 5y - 5
| 6 or 4 | |
| 7 or -2 | |
| 9 or -9 | |
| -8 or -9 |
The first step to solve a quadratic expression that's not set to zero is to solve the equation so that it is set to zero:
y2 + 22y + 67 = 5y - 5
y2 + 22y + 67 + 5 = 5y
y2 + 22y - 5y + 72 = 0
y2 + 17y + 72 = 0
Next, factor the quadratic equation:
y2 + 17y + 72 = 0
(y + 8)(y + 9) = 0
For this expression to be true, the left side of the expression must equal zero. Therefore, either (y + 8) or (y + 9) must equal zero:
If (y + 8) = 0, y must equal -8
If (y + 9) = 0, y must equal -9
So the solution is that y = -8 or -9
A(n) __________ is two expressions separated by an equal sign.
problem |
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expression |
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formula |
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equation |
An equation is two expressions separated by an equal sign. The key to solving equations is to repeatedly do the same thing to both sides of the equation until the variable is isolated on one side of the equal sign and the answer on the other.