| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
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Which of the following statements about math operations is incorrect?
you can subtract monomials that have the same variable and the same exponent |
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you can multiply monomials that have different variables and different exponents |
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you can add monomials that have the same variable and the same exponent |
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all of these statements are correct |
You can only add or subtract monomials that have the same variable and the same exponent. For example, 2a + 4a = 6a and 4a2 - a2 = 3a2 but 2a + 4b and 7a - 3b cannot be combined. However, you can multiply and divide monomials with unlike terms. For example, 2a x 6b = 12ab.
Solve for c:
5c - 7 > \( \frac{c}{-6} \)
| c > -1\(\frac{13}{23}\) | |
| c > 1\(\frac{11}{31}\) | |
| c > -1\(\frac{1}{9}\) | |
| c > -1\(\frac{7}{8}\) |
To solve this equation, repeatedly do the same thing to both sides of the equation until the variable is isolated on one side of the > sign and the answer on the other.
5c - 7 > \( \frac{c}{-6} \)
-6 x (5c - 7) > c
(-6 x 5c) + (-6 x -7) > c
-30c + 42 > c
-30c + 42 - c > 0
-30c - c > -42
-31c > -42
c > \( \frac{-42}{-31} \)
c > 1\(\frac{11}{31}\)
Solve -4c + 7c = 7c - 9x + 8 for c in terms of x.
| x + 1\(\frac{3}{5}\) | |
| 1\(\frac{5}{11}\)x - \(\frac{8}{11}\) | |
| -5x - 1\(\frac{2}{3}\) | |
| x - \(\frac{5}{11}\) |
To solve this equation, isolate the variable for which you are solving (c) on one side of the equation and put everything else on the other side.
-4c + 7x = 7c - 9x + 8
-4c = 7c - 9x + 8 - 7x
-4c - 7c = -9x + 8 - 7x
-11c = -16x + 8
c = \( \frac{-16x + 8}{-11} \)
c = \( \frac{-16x}{-11} \) + \( \frac{8}{-11} \)
c = 1\(\frac{5}{11}\)x - \(\frac{8}{11}\)
Breaking apart a quadratic expression into a pair of binomials is called:
deconstructing |
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normalizing |
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factoring |
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squaring |
To factor a quadratic expression, apply the FOIL (First, Outside, Inside, Last) method in reverse.
Solve for a:
6a - 8 > 7 - a
| a > 5 | |
| a > -\(\frac{3}{4}\) | |
| a > 2\(\frac{1}{7}\) | |
| a > -1\(\frac{1}{2}\) |
To solve this equation, repeatedly do the same thing to both sides of the equation until the variable is isolated on one side of the > sign and the answer on the other.
6a - 8 > 7 - a
6a > 7 - a + 8
6a + a > 7 + 8
7a > 15
a > \( \frac{15}{7} \)
a > 2\(\frac{1}{7}\)