When solving an equation with two variables, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)
Solve -8c - 2c = 3c - z + 8 for c in terms of z.
| -1\(\frac{1}{5}\)z + \(\frac{4}{5}\) | |
| -\(\frac{1}{11}\)z - \(\frac{8}{11}\) | |
| \(\frac{5}{6}\)z + \(\frac{1}{6}\) | |
| -1\(\frac{1}{8}\)z + \(\frac{7}{8}\) |