ASVAB Math Knowledge Practice Test 108482 Results

Your Results Global Average
Questions 5 5
Correct 0 2.83
Score 0% 57%

Review

1

Solve for y:
y2 - 7y - 49 = -3y - 4

48% Answer Correctly
5 or 5
6 or -7
-8 or -8
-5 or 9

Solution

The first step to solve a quadratic expression that's not set to zero is to solve the equation so that it is set to zero:

y2 - 7y - 49 = -3y - 4
y2 - 7y - 49 + 4 = -3y
y2 - 7y + 3y - 45 = 0
y2 - 4y - 45 = 0

Next, factor the quadratic equation:

y2 - 4y - 45 = 0
(y + 5)(y - 9) = 0

For this expression to be true, the left side of the expression must equal zero. Therefore, either (y + 5) or (y - 9) must equal zero:

If (y + 5) = 0, y must equal -5
If (y - 9) = 0, y must equal 9

So the solution is that y = -5 or 9


2

Breaking apart a quadratic expression into a pair of binomials is called:

74% Answer Correctly

factoring

deconstructing

squaring

normalizing


Solution

To factor a quadratic expression, apply the FOIL (First, Outside, Inside, Last) method in reverse.


3

If the length of AB equals the length of BD, point B __________ this line segment.

45% Answer Correctly

bisects

midpoints

intersects

trisects


Solution

A line segment is a portion of a line with a measurable length. The midpoint of a line segment is the point exactly halfway between the endpoints. The midpoint bisects (cuts in half) the line segment.


4

Solve for b:
3b + 1 > \( \frac{b}{-1} \)

44% Answer Correctly
b > 1\(\frac{5}{13}\)
b > -\(\frac{21}{55}\)
b > -1\(\frac{1}{11}\)
b > -\(\frac{1}{4}\)

Solution

To solve this equation, repeatedly do the same thing to both sides of the equation until the variable is isolated on one side of the > sign and the answer on the other.

3b + 1 > \( \frac{b}{-1} \)
-1 x (3b + 1) > b
(-1 x 3b) + (-1 x 1) > b
-3b - 1 > b
-3b - 1 - b > 0
-3b - b > 1
-4b > 1
b > \( \frac{1}{-4} \)
b > -\(\frac{1}{4}\)


5

What is the area of a circle with a radius of 4?

69% Answer Correctly
81π
16π

Solution

The formula for area is πr2:

a = πr2
a = π(42)
a = 16π