When solving an equation with two variables, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)
Solve 5c - 3c = 3c - z + 5 for c in terms of z.
| 2z + 1 | |
| -\(\frac{1}{2}\)z - 1 | |
| z + 2\(\frac{1}{2}\) | |
| z + 3 |