To solve this equation, repeatedly do the same thing to both sides of the equation until the variable is isolated on one side of the equal sign and the answer on the other.

a - 3 = \( \frac{a}{5} \)
5 x (a - 3) = a
(5 x a) + (5 x -3) = a
5a - 15 = a
5a - 15 - a = 0
5a - a = 15
4a = 15
a = \( \frac{15}{4} \)
a = 3\(\frac{3}{4}\)

The formula for circumference is circle diameter x π:

c = πd
c = 5π

You can only add or subtract monomials that have the same variable and the same exponent. For example, 2a + 4a = 6a and 4a² - a² = 3a² but 2a + 4b and 7a - 3b cannot be combined. However, you can multiply and divide monomials with unlike terms. For example, 2a x 6b = 12ab.

The entire length of this line is represented by AD which is AB + BD:

AD = AB + BD

The first step to solve a quadratic expression that's not set to zero is to solve the equation so that it is set to zero:

x² + 9x + 11 = -x + 2
x² + 9x + 11 - 2 = -x
x² + 9x + x + 9 = 0
x² + 10x + 9 = 0

Next, factor the quadratic equation:

x² + 10x + 9 = 0
(x + 1)(x + 9) = 0

For this expression to be true, the left side of the expression must equal zero. Therefore, either (x + 1) or (x + 9) must equal zero:

If (x + 1) = 0, x must equal -1
If (x + 9) = 0, x must equal -9

So the solution is that x = -1 or -9