When solving an equation with two variables, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)
Solve c - 5c = 6c + 9x + 3 for c in terms of x.
| -2\(\frac{4}{5}\)x - \(\frac{3}{5}\) | |
| \(\frac{3}{8}\)x + \(\frac{3}{8}\) | |
| 4x + 1 | |
| -\(\frac{2}{5}\)x - 1\(\frac{1}{5}\) |