| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 2.63 |
| Score | 0% | 53% |
The formula for volume of a cube in terms of height (h), length (l), and width (w) is which of the following?
h x l x w |
|
2lw x 2wh + 2lh |
|
h2 x l2 x w2 |
|
lw x wh + lh |
A cube is a rectangular solid box with a height (h), length (l), and width (w). The volume is h x l x w and the surface area is 2lw x 2wh + 2lh.
The endpoints of this line segment are at (-2, -3) and (2, -1). What is the slope-intercept equation for this line?
| y = -1\(\frac{1}{2}\)x + 1 | |
| y = -x + 2 | |
| y = \(\frac{1}{2}\)x - 2 | |
| y = 2\(\frac{1}{2}\)x - 1 |
The slope-intercept equation for a line is y = mx + b where m is the slope and b is the y-intercept of the line. From the graph, you can see that the y-intercept (the y-value from the point where the line crosses the y-axis) is -2. The slope of this line is the change in y divided by the change in x. The endpoints of this line segment are at (-2, -3) and (2, -1) so the slope becomes:
m = \( \frac{\Delta y}{\Delta x} \) = \( \frac{(-1.0) - (-3.0)}{(2) - (-2)} \) = \( \frac{2}{4} \)Plugging these values into the slope-intercept equation:
y = \(\frac{1}{2}\)x - 2
Simplify (y + 8)(y - 8)
| y2 + 16y + 64 | |
| y2 - 64 | |
| y2 - 16y + 64 | |
| 48 |
To multiply binomials, use the FOIL method. FOIL stands for First, Outside, Inside, Last and refers to the position of each term in the parentheses:
(y + 8)(y - 8)
(y x y) + (y x -8) + (8 x y) + (8 x -8)
y2 - 8y + 8y - 64
y2 - 64
If the base of this triangle is 1 and the height is 3, what is the area?
| 1\(\frac{1}{2}\) | |
| 71\(\frac{1}{2}\) | |
| 58\(\frac{1}{2}\) | |
| 12\(\frac{1}{2}\) |
The area of a triangle is equal to ½ base x height:
a = ½bh
a = ½ x 1 x 3 = \( \frac{3}{2} \) = 1\(\frac{1}{2}\)
Solve -c + 8c = -6c + 5y + 9 for c in terms of y.
| -\(\frac{3}{5}\)y + 1\(\frac{4}{5}\) | |
| -y + 3 | |
| 5y + 2 | |
| 3\(\frac{1}{4}\)y - \(\frac{1}{4}\) |
To solve this equation, isolate the variable for which you are solving (c) on one side of the equation and put everything else on the other side.
-c + 8y = -6c + 5y + 9
-c = -6c + 5y + 9 - 8y
-c + 6c = 5y + 9 - 8y
5c = -3y + 9
c = \( \frac{-3y + 9}{5} \)
c = \( \frac{-3y}{5} \) + \( \frac{9}{5} \)
c = -\(\frac{3}{5}\)y + 1\(\frac{4}{5}\)