ASVAB Math Knowledge Practice Test 112446 Results

Your Results Global Average
Questions 5 5
Correct 0 2.63
Score 0% 53%

Review

1

The formula for volume of a cube in terms of height (h), length (l), and width (w) is which of the following?

67% Answer Correctly

h x l x w

2lw x 2wh + 2lh

h2 x l2 x w2

lw x wh + lh


Solution

A cube is a rectangular solid box with a height (h), length (l), and width (w). The volume is h x l x w and the surface area is 2lw x 2wh + 2lh.


2

The endpoints of this line segment are at (-2, -3) and (2, -1). What is the slope-intercept equation for this line?

41% Answer Correctly
y = -1\(\frac{1}{2}\)x + 1
y = -x + 2
y = \(\frac{1}{2}\)x - 2
y = 2\(\frac{1}{2}\)x - 1

Solution

The slope-intercept equation for a line is y = mx + b where m is the slope and b is the y-intercept of the line. From the graph, you can see that the y-intercept (the y-value from the point where the line crosses the y-axis) is -2. The slope of this line is the change in y divided by the change in x. The endpoints of this line segment are at (-2, -3) and (2, -1) so the slope becomes:

m = \( \frac{\Delta y}{\Delta x} \) = \( \frac{(-1.0) - (-3.0)}{(2) - (-2)} \) = \( \frac{2}{4} \)
m = \(\frac{1}{2}\)

Plugging these values into the slope-intercept equation:

y = \(\frac{1}{2}\)x - 2


3

Simplify (y + 8)(y - 8)

62% Answer Correctly
y2 + 16y + 64
y2 - 64
y2 - 16y + 64
48

Solution

To multiply binomials, use the FOIL method. FOIL stands for First, Outside, Inside, Last and refers to the position of each term in the parentheses:

(y + 8)(y - 8)
(y x y) + (y x -8) + (8 x y) + (8 x -8)
y2 - 8y + 8y - 64
y2 - 64


4

If the base of this triangle is 1 and the height is 3, what is the area?

58% Answer Correctly
1\(\frac{1}{2}\)
71\(\frac{1}{2}\)
58\(\frac{1}{2}\)
12\(\frac{1}{2}\)

Solution

The area of a triangle is equal to ½ base x height:

a = ½bh
a = ½ x 1 x 3 = \( \frac{3}{2} \) = 1\(\frac{1}{2}\)


5

Solve -c + 8c = -6c + 5y + 9 for c in terms of y.

34% Answer Correctly
-\(\frac{3}{5}\)y + 1\(\frac{4}{5}\)
-y + 3
5y + 2
3\(\frac{1}{4}\)y - \(\frac{1}{4}\)

Solution

To solve this equation, isolate the variable for which you are solving (c) on one side of the equation and put everything else on the other side.

-c + 8y = -6c + 5y + 9
-c = -6c + 5y + 9 - 8y
-c + 6c = 5y + 9 - 8y
5c = -3y + 9
c = \( \frac{-3y + 9}{5} \)
c = \( \frac{-3y}{5} \) + \( \frac{9}{5} \)
c = -\(\frac{3}{5}\)y + 1\(\frac{4}{5}\)