ASVAB Math Knowledge Practice Test 114120 Results

Your Results Global Average
Questions 5 5
Correct 0 3.41
Score 0% 68%

Review

1

A cylinder with a radius (r) and a height (h) has a surface area of:

53% Answer Correctly

2(π r2) + 2π rh

π r2h

4π r2

π r2h2


Solution

A cylinder is a solid figure with straight parallel sides and a circular or oval cross section with a radius (r) and a height (h). The volume of a cylinder is π r2h and the surface area is 2(π r2) + 2π rh.


2

If side x = 9cm, side y = 9cm, and side z = 9cm what is the perimeter of this triangle?

84% Answer Correctly
21cm
29cm
27cm
31cm

Solution

The perimeter of a triangle is the sum of the lengths of its sides:

p = x + y + z
p = 9cm + 9cm + 9cm = 27cm


3

If a = 2, b = 9, c = 7, and d = 6, what is the perimeter of this quadrilateral?

88% Answer Correctly
19
21
24
25

Solution

Perimeter is equal to the sum of the four sides:

p = a + b + c + d
p = 2 + 9 + 7 + 6
p = 24


4

Solve for c:
c2 - 6c - 35 = -2c - 3

48% Answer Correctly
5 or -7
-4 or 8
2 or -7
9 or -5

Solution

The first step to solve a quadratic expression that's not set to zero is to solve the equation so that it is set to zero:

c2 - 6c - 35 = -2c - 3
c2 - 6c - 35 + 3 = -2c
c2 - 6c + 2c - 32 = 0
c2 - 4c - 32 = 0

Next, factor the quadratic equation:

c2 - 4c - 32 = 0
(c + 4)(c - 8) = 0

For this expression to be true, the left side of the expression must equal zero. Therefore, either (c + 4) or (c - 8) must equal zero:

If (c + 4) = 0, c must equal -4
If (c - 8) = 0, c must equal 8

So the solution is that c = -4 or 8


5

If the area of this square is 64, what is the length of one of the diagonals?

68% Answer Correctly
9\( \sqrt{2} \)
4\( \sqrt{2} \)
8\( \sqrt{2} \)
3\( \sqrt{2} \)

Solution

To find the diagonal we need to know the length of one of the square's sides. We know the area and the area of a square is the length of one side squared:

a = s2

so the length of one side of the square is:

s = \( \sqrt{a} \) = \( \sqrt{64} \) = 8

The Pythagorean theorem defines the square of the hypotenuse (diagonal) of a triangle with a right angle as the sum of the squares of the other two sides:

c2 = a2 + b2
c2 = 82 + 82
c2 = 128
c = \( \sqrt{128} \) = \( \sqrt{64 x 2} \) = \( \sqrt{64} \) \( \sqrt{2} \)
c = 8\( \sqrt{2} \)