| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 3.41 |
| Score | 0% | 68% |
A cylinder with a radius (r) and a height (h) has a surface area of:
2(π r2) + 2π rh |
|
π r2h |
|
4π r2 |
|
π r2h2 |
A cylinder is a solid figure with straight parallel sides and a circular or oval cross section with a radius (r) and a height (h). The volume of a cylinder is π r2h and the surface area is 2(π r2) + 2π rh.
If side x = 9cm, side y = 9cm, and side z = 9cm what is the perimeter of this triangle?
| 21cm | |
| 29cm | |
| 27cm | |
| 31cm |
The perimeter of a triangle is the sum of the lengths of its sides:
p = x + y + z
p = 9cm + 9cm + 9cm = 27cm
If a = 2, b = 9, c = 7, and d = 6, what is the perimeter of this quadrilateral?
| 19 | |
| 21 | |
| 24 | |
| 25 |
Perimeter is equal to the sum of the four sides:
p = a + b + c + d
p = 2 + 9 + 7 + 6
p = 24
Solve for c:
c2 - 6c - 35 = -2c - 3
| 5 or -7 | |
| -4 or 8 | |
| 2 or -7 | |
| 9 or -5 |
The first step to solve a quadratic expression that's not set to zero is to solve the equation so that it is set to zero:
c2 - 6c - 35 = -2c - 3
c2 - 6c - 35 + 3 = -2c
c2 - 6c + 2c - 32 = 0
c2 - 4c - 32 = 0
Next, factor the quadratic equation:
c2 - 4c - 32 = 0
(c + 4)(c - 8) = 0
For this expression to be true, the left side of the expression must equal zero. Therefore, either (c + 4) or (c - 8) must equal zero:
If (c + 4) = 0, c must equal -4
If (c - 8) = 0, c must equal 8
So the solution is that c = -4 or 8
If the area of this square is 64, what is the length of one of the diagonals?
| 9\( \sqrt{2} \) | |
| 4\( \sqrt{2} \) | |
| 8\( \sqrt{2} \) | |
| 3\( \sqrt{2} \) |
To find the diagonal we need to know the length of one of the square's sides. We know the area and the area of a square is the length of one side squared:
a = s2
so the length of one side of the square is:
s = \( \sqrt{a} \) = \( \sqrt{64} \) = 8
The Pythagorean theorem defines the square of the hypotenuse (diagonal) of a triangle with a right angle as the sum of the squares of the other two sides:
c2 = a2 + b2
c2 = 82 + 82
c2 = 128
c = \( \sqrt{128} \) = \( \sqrt{64 x 2} \) = \( \sqrt{64} \) \( \sqrt{2} \)
c = 8\( \sqrt{2} \)