ASVAB Math Knowledge Practice Test 114222 Results

Your Results Global Average
Questions 5 5
Correct 0 3.27
Score 0% 65%

Review

1

If angle a = 24° and angle b = 66° what is the length of angle c?

71% Answer Correctly
70°
90°
92°
133°

Solution

The sum of the interior angles of a triangle is 180°:
180° = a° + b° + c°
c° = 180° - a° - b°
c° = 180° - 24° - 66° = 90°


2

If angle a = 37° and angle b = 42° what is the length of angle d?

56% Answer Correctly
143°
158°
160°
126°

Solution

An exterior angle of a triangle is equal to the sum of the two interior angles that are opposite:

d° = b° + c°

To find angle c, remember that the sum of the interior angles of a triangle is 180°:

180° = a° + b° + c°
c° = 180° - a° - b°
c° = 180° - 37° - 42° = 101°

So, d° = 42° + 101° = 143°

A shortcut to get this answer is to remember that angles around a line add up to 180°:

a° + d° = 180°
d° = 180° - a°
d° = 180° - 37° = 143°


3

Simplify 7a x 2b.

86% Answer Correctly
14\( \frac{a}{b} \)
9ab
14a2b2
14ab

Solution

To multiply monomials, multiply the coefficients (the numbers that come before the variables) of each term, add the exponents of like variables, and multiply the different variables together.

7a x 2b = (7 x 2) (a x b) = 14ab


4

If the length of AB equals the length of BD, point B __________ this line segment.

46% Answer Correctly

midpoints

trisects

bisects

intersects


Solution

A line segment is a portion of a line with a measurable length. The midpoint of a line segment is the point exactly halfway between the endpoints. The midpoint bisects (cuts in half) the line segment.


5

If the area of this square is 81, what is the length of one of the diagonals?

69% Answer Correctly
5\( \sqrt{2} \)
3\( \sqrt{2} \)
2\( \sqrt{2} \)
9\( \sqrt{2} \)

Solution

To find the diagonal we need to know the length of one of the square's sides. We know the area and the area of a square is the length of one side squared:

a = s2

so the length of one side of the square is:

s = \( \sqrt{a} \) = \( \sqrt{81} \) = 9

The Pythagorean theorem defines the square of the hypotenuse (diagonal) of a triangle with a right angle as the sum of the squares of the other two sides:

c2 = a2 + b2
c2 = 92 + 92
c2 = 162
c = \( \sqrt{162} \) = \( \sqrt{81 x 2} \) = \( \sqrt{81} \) \( \sqrt{2} \)
c = 9\( \sqrt{2} \)