When solving an equation with two variables, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)
Solve 4a - 6a = 3a + 8y + 1 for a in terms of y.
14y + 1 | |
-2\(\frac{1}{3}\)y + 2\(\frac{1}{3}\) | |
1\(\frac{1}{3}\)y - 2\(\frac{2}{3}\) | |
-\(\frac{10}{17}\)y - \(\frac{1}{17}\) |