When solving an equation with two variables, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)
Solve 4c - 8c = -c + 6y - 3 for c in terms of y.
| y - 2\(\frac{2}{3}\) | |
| 2\(\frac{4}{5}\)y - \(\frac{3}{5}\) | |
| 1\(\frac{3}{5}\)y + \(\frac{4}{5}\) | |
| 1\(\frac{3}{4}\)y - \(\frac{1}{2}\) |