ASVAB Math Knowledge Practice Test 11951 Results

Your Results Global Average
Questions 5 5
Correct 0 2.84
Score 0% 57%

Review

1

Simplify (5a)(8ab) - (6a2)(5b).

59% Answer Correctly
10a2b
-10ab2
70a2b
70ab2

Solution

To multiply monomials, multiply the coefficients (the numbers that come before the variables) of each term, add the exponents of like variables, and multiply the different variables together.

(5a)(8ab) - (6a2)(5b)
(5 x 8)(a x a x b) - (6 x 5)(a2 x b)
(40)(a1+1 x b) - (30)(a2b)
40a2b - 30a2b
10a2b


2

Solve for b:
3b + 2 < \( \frac{b}{1} \)

44% Answer Correctly
b < 3\(\frac{12}{17}\)
b < -1
b < -1\(\frac{1}{9}\)
b < -\(\frac{40}{57}\)

Solution

To solve this equation, repeatedly do the same thing to both sides of the equation until the variable is isolated on one side of the < sign and the answer on the other.

3b + 2 < \( \frac{b}{1} \)
1 x (3b + 2) < b
(1 x 3b) + (1 x 2) < b
3b + 2 < b
3b + 2 - b < 0
3b - b < -2
2b < -2
b < \( \frac{-2}{2} \)
b < -1


3

Solve for b:
-3b + 2 = 6 - b

58% Answer Correctly
-4
-\(\frac{2}{3}\)
-2
\(\frac{3}{4}\)

Solution

To solve this equation, repeatedly do the same thing to both sides of the equation until the variable is isolated on one side of the equal sign and the answer on the other.

-3b + 2 = 6 - b
-3b = 6 - b - 2
-3b + b = 6 - 2
-2b = 4
b = \( \frac{4}{-2} \)
b = -2


4

The dimensions of this trapezoid are a = 5, b = 6, c = 7, d = 3, and h = 3. What is the area?

50% Answer Correctly
24
34
27\(\frac{1}{2}\)
13\(\frac{1}{2}\)

Solution

The area of a trapezoid is one-half the sum of the lengths of the parallel sides multiplied by the height:

a = ½(b + d)(h)
a = ½(6 + 3)(3)
a = ½(9)(3)
a = ½(27) = \( \frac{27}{2} \)
a = 13\(\frac{1}{2}\)


5

What is 6a3 - 8a3?

73% Answer Correctly
a36
-2
-2a3
48a6

Solution

To combine like terms, add or subtract the coefficients (the numbers that come before the variables) of terms that have the same variable raised to the same exponent.

6a3 - 8a3 = -2a3