ASVAB Math Knowledge Practice Test 120929

Question 1 of 5
Two Variables

When solving an equation with two variables, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)

Solve -6c + 4c = -8c - 3y + 1 for c in terms of y.

-2\(\frac{1}{8}\)y - \(\frac{3}{4}\)
-3\(\frac{1}{2}\)y + \(\frac{1}{2}\)
\(\frac{8}{11}\)y - \(\frac{3}{11}\)
-4y - 3