ASVAB Math Knowledge Practice Test 121294 Results

Your Results Global Average
Questions 5 5
Correct 0 2.68
Score 0% 54%

Review

1

What is 7a3 - 3a3?

73% Answer Correctly
10
4a3
4
4a6

Solution

To combine like terms, add or subtract the coefficients (the numbers that come before the variables) of terms that have the same variable raised to the same exponent.

7a3 - 3a3 = 4a3


2

Solve for y:
9y + 3 > 6 - 6y

55% Answer Correctly
y > 1\(\frac{1}{7}\)
y > -2\(\frac{1}{3}\)
y > \(\frac{1}{5}\)
y > -2

Solution

To solve this equation, repeatedly do the same thing to both sides of the equation until the variable is isolated on one side of the > sign and the answer on the other.

9y + 3 > 6 - 6y
9y > 6 - 6y - 3
9y + 6y > 6 - 3
15y > 3
y > \( \frac{3}{15} \)
y > \(\frac{1}{5}\)


3

On this circle, a line segment connecting point A to point D is called:

46% Answer Correctly

radius

chord

diameter

circumference


Solution

A circle is a figure in which each point around its perimeter is an equal distance from the center. The radius of a circle is the distance between the center and any point along its perimeter. A chord is a line segment that connects any two points along its perimeter. The diameter of a circle is the length of a chord that passes through the center of the circle and equals twice the circle's radius (2r).


4

On this circle, line segment CD is the:

46% Answer Correctly

radius

circumference

chord

diameter


Solution

A circle is a figure in which each point around its perimeter is an equal distance from the center. The radius of a circle is the distance between the center and any point along its perimeter. A chord is a line segment that connects any two points along its perimeter. The diameter of a circle is the length of a chord that passes through the center of the circle and equals twice the circle's radius (2r).


5

The dimensions of this cylinder are height (h) = 1 and radius (r) = 4. What is the surface area?

48% Answer Correctly
130π
12π
36π
40π

Solution

The surface area of a cylinder is 2πr2 + 2πrh:

sa = 2πr2 + 2πrh
sa = 2π(42) + 2π(4 x 1)
sa = 2π(16) + 2π(4)
sa = (2 x 16)π + (2 x 4)π
sa = 32π + 8π
sa = 40π