When solving an equation with two variables, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)
Solve b - 2b = 3b + 3z + 1 for b in terms of z.
| 2\(\frac{1}{2}\)z + 1\(\frac{1}{6}\) | |
| z + \(\frac{3}{4}\) | |
| -z - \(\frac{5}{8}\) | |
| -2\(\frac{1}{2}\)z - \(\frac{1}{2}\) |