| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 2.79 |
| Score | 0% | 56% |
Simplify (2a)(5ab) + (7a2)(7b).
| 39ab2 | |
| 39a2b | |
| 59a2b | |
| 59ab2 |
To multiply monomials, multiply the coefficients (the numbers that come before the variables) of each term, add the exponents of like variables, and multiply the different variables together.
(2a)(5ab) + (7a2)(7b)
(2 x 5)(a x a x b) + (7 x 7)(a2 x b)
(10)(a1+1 x b) + (49)(a2b)
10a2b + 49a2b
59a2b
Solve 7c - c = -8c - 4x + 1 for c in terms of x.
| 1\(\frac{1}{2}\)x + 3\(\frac{1}{2}\) | |
| -\(\frac{1}{5}\)x + \(\frac{1}{15}\) | |
| -2\(\frac{1}{2}\)x + \(\frac{1}{2}\) | |
| -1\(\frac{1}{6}\)x - 1\(\frac{1}{6}\) |
To solve this equation, isolate the variable for which you are solving (c) on one side of the equation and put everything else on the other side.
7c - x = -8c - 4x + 1
7c = -8c - 4x + 1 + x
7c + 8c = -4x + 1 + x
15c = -3x + 1
c = \( \frac{-3x + 1}{15} \)
c = \( \frac{-3x}{15} \) + \( \frac{1}{15} \)
c = -\(\frac{1}{5}\)x + \(\frac{1}{15}\)
If the base of this triangle is 5 and the height is 4, what is the area?
| 10 | |
| 24\(\frac{1}{2}\) | |
| 84 | |
| 45\(\frac{1}{2}\) |
The area of a triangle is equal to ½ base x height:
a = ½bh
a = ½ x 5 x 4 = \( \frac{20}{2} \) = 10
Which of the following statements about a parallelogram is not true?
the area of a parallelogram is base x height |
|
a parallelogram is a quadrilateral |
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opposite sides and adjacent angles are equal |
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the perimeter of a parallelogram is the sum of the lengths of all sides |
A parallelogram is a quadrilateral with two sets of parallel sides. Opposite sides (a = c, b = d) and angles (red = red, blue = blue) are equal. The area of a parallelogram is base x height and the perimeter is the sum of the lengths of all sides (a + b + c + d).
What is the circumference of a circle with a radius of 18?
| 12π | |
| 18π | |
| 20π | |
| 36π |
The formula for circumference is circle diameter x π. Circle diameter is 2 x radius:
c = πd
c = π(2 * r)
c = π(2 * 18)
c = 36π