When solving an equation with two variables, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)
Solve -6c + 5c = -3c - 4y - 1 for c in terms of y.
| \(\frac{5}{14}\)y - \(\frac{4}{7}\) | |
| \(\frac{1}{7}\)y + 1 | |
| 3y + \(\frac{1}{3}\) | |
| y - 1\(\frac{2}{3}\) |