When solving an equation with two variables, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)
Solve 2c + 8c = 7c - 5x + 2 for c in terms of x.
| -\(\frac{1}{13}\)x - \(\frac{6}{13}\) | |
| 2\(\frac{3}{5}\)x - \(\frac{2}{5}\) | |
| \(\frac{1}{2}\)x + 2\(\frac{1}{4}\) | |
| -1\(\frac{5}{8}\)x - \(\frac{3}{4}\) |