When solving an equation with two variables, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)
Solve -6a + 5a = 6a + 4z + 2 for a in terms of z.
| -2\(\frac{1}{3}\)z + \(\frac{1}{3}\) | |
| \(\frac{1}{12}\)z - \(\frac{1}{6}\) | |
| 2\(\frac{2}{3}\)z - 3 | |
| -8z + 9 |