When solving an equation with two variables, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)
Solve 2c - 5c = -8c + 7z - 6 for c in terms of z.
| -\(\frac{1}{3}\)z - \(\frac{1}{6}\) | |
| 4\(\frac{1}{2}\)z - 3\(\frac{1}{2}\) | |
| 13z + 4 | |
| 1\(\frac{1}{5}\)z - \(\frac{3}{5}\) |