ASVAB Math Knowledge Practice Test 123818 Results

Your Results Global Average
Questions 5 5
Correct 0 2.66
Score 0% 53%

Review

1

Solve for z:
9z - 6 = \( \frac{z}{-7} \)

46% Answer Correctly
-1\(\frac{5}{43}\)
\(\frac{21}{32}\)
-\(\frac{9}{73}\)
4

Solution

To solve this equation, repeatedly do the same thing to both sides of the equation until the variable is isolated on one side of the equal sign and the answer on the other.

9z - 6 = \( \frac{z}{-7} \)
-7 x (9z - 6) = z
(-7 x 9z) + (-7 x -6) = z
-63z + 42 = z
-63z + 42 - z = 0
-63z - z = -42
-64z = -42
z = \( \frac{-42}{-64} \)
z = \(\frac{21}{32}\)


2

What is the area of a circle with a radius of 2?

69% Answer Correctly
49π

Solution

The formula for area is πr2:

a = πr2
a = π(22)
a = 4π


3

The formula for the area of a circle is which of the following?

24% Answer Correctly

c = π r2

c = π r

c = π d2

c = π d


Solution

The circumference of a circle is the distance around its perimeter and equals π (approx. 3.14159) x diameter: c = π d. The area of a circle is π x (radius)2 : a = π r2.


4

Order the following types of angle from least number of degrees to most number of degrees.

75% Answer Correctly

right, acute, obtuse

acute, obtuse, right

acute, right, obtuse

right, obtuse, acute


Solution

An acute angle measures less than 90°, a right angle measures 90°, and an obtuse angle measures more than 90°.


5

A cylinder with a radius (r) and a height (h) has a surface area of:

53% Answer Correctly

4π r2

2(π r2) + 2π rh

π r2h2

π r2h


Solution

A cylinder is a solid figure with straight parallel sides and a circular or oval cross section with a radius (r) and a height (h). The volume of a cylinder is π r2h and the surface area is 2(π r2) + 2π rh.